![How do you find the equations for the tangent plane to the surface x^2+2z^2= y^2 through (1, 3, -2)? | Socratic How do you find the equations for the tangent plane to the surface x^2+2z^2= y^2 through (1, 3, -2)? | Socratic](https://useruploads.socratic.org/arcAwri2T5yDPWR4HveK_Image2.jpg)
How do you find the equations for the tangent plane to the surface x^2+2z^2= y^2 through (1, 3, -2)? | Socratic
![integration - Finding the surface area of the paraboloid $z = 1 - x^2 - y^2$ that lies above the plane $z = -4$ - Mathematics Stack Exchange integration - Finding the surface area of the paraboloid $z = 1 - x^2 - y^2$ that lies above the plane $z = -4$ - Mathematics Stack Exchange](https://i.stack.imgur.com/9jc8G.jpg)
integration - Finding the surface area of the paraboloid $z = 1 - x^2 - y^2$ that lies above the plane $z = -4$ - Mathematics Stack Exchange
![integration - Finding the surface area of the paraboloid $z = 1 - x^2 - y^2$ that lies above the plane $z = -4$ - Mathematics Stack Exchange integration - Finding the surface area of the paraboloid $z = 1 - x^2 - y^2$ that lies above the plane $z = -4$ - Mathematics Stack Exchange](https://i.stack.imgur.com/p991B.jpg)
integration - Finding the surface area of the paraboloid $z = 1 - x^2 - y^2$ that lies above the plane $z = -4$ - Mathematics Stack Exchange
![Sketch a graph of the paraboloid z = x^2 + y^2. Determine whether the outward normal vector N should point in the + k or - k direction, and calculate N in Sketch a graph of the paraboloid z = x^2 + y^2. Determine whether the outward normal vector N should point in the + k or - k direction, and calculate N in](https://homework.study.com/cimages/multimages/16/tut75g8t3328327554121365302.png)
Sketch a graph of the paraboloid z = x^2 + y^2. Determine whether the outward normal vector N should point in the + k or - k direction, and calculate N in
![The equation of a line 4x-4y-z+11=0=x+2y-z-1 can be put as x/2=(y-2)/1=(z-3)/4 (b) (x-2)/2=(y-2)/1=z/4 (x-2)/2=y/1=(z-3)/4 (d) None of these The equation of a line 4x-4y-z+11=0=x+2y-z-1 can be put as x/2=(y-2)/1=(z-3)/4 (b) (x-2)/2=(y-2)/1=z/4 (x-2)/2=y/1=(z-3)/4 (d) None of these](https://d10lpgp6xz60nq.cloudfront.net/web-thumb/42433_web.png)
The equation of a line 4x-4y-z+11=0=x+2y-z-1 can be put as x/2=(y-2)/1=(z-3)/4 (b) (x-2)/2=(y-2)/1=z/4 (x-2)/2=y/1=(z-3)/4 (d) None of these
![Portion of sphere x 2 + y 2 + z 2 ≤ 1 in the first octant x, y, z ≥ 0. | Download Scientific Diagram Portion of sphere x 2 + y 2 + z 2 ≤ 1 in the first octant x, y, z ≥ 0. | Download Scientific Diagram](https://www.researchgate.net/profile/Jose-Galan-Garcia/publication/356169429/figure/fig2/AS:1089319662026774@1636725454392/Portion-of-sphere-x-2-y-2-z-2-1-in-the-first-octant-x-y-z-0_Q640.jpg)